A parallel beam of monochromatic light of wavelength λ is used in a Young’s double slit experiment. The siits are separated by a distance d and the screen is placed parallel to the plane of the slits. The incident beam makes an angle θ = sin –1 
with the normal to the plane of the slits. A transparent sheet of refractive index. ' μ ' and thickness t = 
is introduced infront of one of the slit. find the intensity at the geometrical centre .
Text Solution
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maximum
Sol. 
clearly, at O, no difference of path due to inside motion of rays.
only path difference = S 1 Q
= d cos (90– θ )
= d sin θ .
= d × 
= 
Net phase difference
so Δφ = 
± ( μ – 1)t. 
= π ± ( μ – 1) 
= 2 π , 0
⇒ constructive interference and hence I res = maximum
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